Given the balanced equation: H2 + Cl2 → 2 HCl ,
how many moles of HCl will be produced if 18.4 g H2 reacts with 127 g Cl2?
To solve this problem, we need to use the balanced equation and the molar masses of each substance involved.
First, let's calculate the number of moles of H2 and Cl2:
Molar mass of H2 = 2 g/mol
Molar mass of Cl2 = 70.9 g/mol
Number of moles of H2 = mass of H2 / molar mass of H2
= 18.4 g / 2 g/mol
= 9.2 mol
Number of moles of Cl2 = mass of Cl2 / molar mass of Cl2
= 127 g / 70.9 g/mol
= 1.79 mol
According to the balanced equation, the mole ratio between H2 and HCl is 1:2. Therefore, for every 1 mole of H2, 2 moles of HCl will be produced.
Since we have 9.2 moles of H2, we can multiply this by the mole ratio to determine the number of moles of HCl produced:
Number of moles of HCl = 9.2 mol H2 * (2 mol HCl / 1 mol H2)
= 18.4 mol HCl
Therefore, 18.4 moles of HCl will be produced when 18.4 g H2 reacts with 127 g Cl2.
To find the number of moles of HCl produced, we need to calculate the number of moles of each reactant and determine which one is limiting.
First, let's calculate the number of moles of H2:
Molar mass of H2 = 2 g/mol
Number of moles of H2 = Mass of H2 / Molar mass of H2
Number of moles of H2 = 18.4 g / 2 g/mol
Number of moles of H2 = 9.2 mol
Next, let's calculate the number of moles of Cl2:
Molar mass of Cl2 = 71 g/mol
Number of moles of Cl2 = Mass of Cl2 / Molar mass of Cl2
Number of moles of Cl2 = 127 g / 71 g/mol
Number of moles of Cl2 = 1.788 mol
According to the balanced equation, the ratio of moles of H2 to HCl is 1:2. Therefore, since 1 mole of H2 forms 2 moles of HCl, the limiting reactant is H2.
Since H2 is the limiting reactant, we can determine the moles of HCl produced using the stoichiometric ratio:
Moles of HCl = Number of moles of H2 * (2 moles of HCl / 1 mole of H2)
Moles of HCl = 9.2 mol * (2 mol / 1 mol)
Moles of HCl = 18.4 mol
Therefore, 18.4 moles of HCl will be produced if 18.4 g H2 reacts with 127 g Cl2.
Cl2 is the limiting reactant
divide by the molar mass to find the number of moles
m.m. Cl2 is 70.9 g