physics

A stone of mass 2.8kg is projected upward with a speed of 5m/s. calculate the maximum height reached. use g=10m/s square.

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  1. Vo = 5 m/s = Initial velocity.
    V = 0 = Final velocity = Velocity at max. ht.
    g = -10 m/s.

    V^2 = Vo^2 + 2g*h. h = ?.

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  2. The answer is 22.3m for the maximum height.

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  3. 0 = 5^2 - 2*10*h,
    20h = 25, h = 1.25 m.

    A 2nd method:
    V = Vo + g*t
    0 = 5 -10t, t = 0.5 s.

    h = Vo*t + 0.5g*t^2,
    h = 5*0.5 - 5*0.5^2,
    h = 2.5 - 1.25 = 1.25 m.

    A 3rd Method:
    KE = PE.
    0.5M*Vo^2 = Mg*h
    1.4*5^2 = 2.8*10*h
    35 = 28h, h = 1.25 m.

    Based on the information given, your answer is incorrect.

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