Series
 👍 0
 👎 0
 👁 220

 👍 0
 👎 0
Respond to this Question
Similar Questions

Arithmetic
The sum of three consecutive terms of a geometric progression is 42, and their product is 512. Find the three terms.

Math, Series
Given that 1/(yx), 1/2y, and 1/yz are consecutive terms of an arithmetic progression, prove that x,y, and z are consecutive terms of a geometric progression.

Math
If 6, p and 14 are consecutive terms in arithmetic progression(A.P) Find the value of p

Arithmetic
The first, second and third terms of a geometric progression are 2k+3, k+6 and k, respectively. Given that all the terms of geometric progression are positive, calculate (a) the value of the constant k (b) the sum to infinity of

Math
The first three terms of an arithmetic progression are 2x, x+4 and 2x+7 respectively. Find the value of x. I have no idea where to go from here – any help would be greatly appreciated, thanks in advance!

MATH
three consecutive terms of a geomentric progression series have product 343 and sum 49/2. fine the numbers. HOW WILL ONE SOLVE THAT? THANKS

arithmetic progression
four positive integers form an arithmetic progression . if the product of the first and the last terms is 70 and the second and third terms are 88, find the first term

math
two arithmetic progression are such that the common difference of both is 8.if the difference b/w their 50th terms is 50.what will be the difference b/w their 80th terms?

arithmetic progression
An arithmetic progression has 3 as its first term. Also, the sum of the first 8 terms is twice the sum of the first 5 terms. Find the common difference.

Math
The common ratio of a geometric progression is 1/2 , the fifth term is 1/80 , and the sum of all of its terms is 127/320 . Find the number of terms in the progression.

Math
The 3rd and 12th terms of an arithmetic progression are 12 and 24 respectively. What is the 50th term?

maths
The sum of first 6 terms of an Arithmetic progression is 6 the product of 2nd term and 5th term is 80 . Find the terms of A.P.
You can view more similar questions or ask a new question.