MATH AGAIN

Given: ∆ABC is isosceles
m∠ACB = 120°
m∠BMC = 60°
CM = 12
Find: AB

M is on line segment AB

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1. surely by now you could have figured this out.

Since ∆ABC is isosceles, ∠A = ∠B = 30°

Therefore, ∆BMC is a 30-60-90 right triangle, with ∠MCB = 90°

So, BC = 12√3

Now drop an altitude from C to AB and use BC to find AB.

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posted by Steve

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