MATH AGAIN
Given: ∆ABC is isosceles
m∠ACB = 120°
m∠BMC = 60°
CM = 12
Find: AB
M is on line segment AB
asked by
Grace

surely by now you could have figured this out.
Since ∆ABC is isosceles, ∠A = ∠B = 30°
Therefore, ∆BMC is a 306090 right triangle, with ∠MCB = 90°
So, BC = 12√3
Now drop an altitude from C to AB and use BC to find AB.posted by Steve
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