math

Given: ∆PQR, m∠R = 90°
m∠PQR = 75°
M ∈ PR , MP = 18
m∠MQR = 60°
Find: RQ

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asked by Grace
  1. Note that ∠MQP = ∠MPQ so ∆QMP is isosceles.

    MQ = MP = 18
    ∆MRQ is 30-60-90, with a hypotenuse of 18

    RQ = 9√3

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    posted by Steve
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    I've checked over and over and found that it's correct. RQ is literally half of MP

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    posted by Sid

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