Physics-torques

Suppose that a meter stick is balanced at its center. A 0.27-kg is positioned at 18 cm from the left end of the meter stick. Where should a 0.28 kg mass be placed to balance the 0.27 kg mass? Express your answer in terms of the position (in cm) of the 0.28-kg mass as measured from the left end of the meter stick.

Compute the total torque about the center due to the two forces. Mass m1 is 50-18 = 32 cm from the center. If x is the distance of mass m2 from the left end, then it is x-50 to the right of the center pivot. Set the total torque equal to zero and solve for x.
-0.27g*(50-18) + 0.28g(x-50) = 0
You can factor out the g.
0.27*32 = 0.28*(x-50)

  1. 👍 0
  2. 👎 0
  3. 👁 582

Respond to this Question

First Name

Your Response

Similar Questions

  1. Physics

    A meter stick balances horizontally on a knife-edge at the 50.0 cm mark. With two 5.00 g coins stacked over the 7.0 cm mark, the stick is found to balance at the 41.0 cm mark. What is the mass of the meter stick? The answer is 38g

    asked by Robert on December 12, 2010
  2. Physics

    A real object is located at the zero end of a meter stick. A large concave mirror at the 100 cm end of the meter stick forms an image of the object at the 72.5 cm position. A small convex mirror placed at the 20.6 cm position

    asked by Anonymous on April 20, 2013
  3. physics

    A .100 kg meter stick is supported at its 40.0 cm mark by a string attached to the ceiling. A .700 kg mass hangs vertically from the 5.00 cm mark. A mass, m, is attached somewhere on the meter stick to keep it horizontal and in

    asked by Anonymous on December 4, 2007
  4. Physics

    One end of a uniform meter stick is placed against a vertical wall. The other end is held by a lightweight cord that makes an angle, theta, with the stick. The coefficient of static friction between the end of the meter stick and

    asked by Karla on April 3, 2007
  1. physics

    The meter stick in the drawing can rotate about an axis located at the 20.0-cm mark. The axis is perpendicular to the screen. A force F acts at the left end; the force is perpendicular to the meter stick and has a magnitude of 175

    asked by alice on February 11, 2011
  2. math

    The diameter of a hydrogen atom is about 5×10^-11 meter. Suppose 8.4×10^8 hydrogen atoms were arranged side by side in a straight line. Multiply these numbers to find the length of this line of atoms. What is the length in

    asked by Claire on May 19, 2016
  3. Physics

    A uniform meter stick balances on a fulcrum placed at the 40 cm mark when a weight W is placed at 30 cm mark. What is the weight of the meter stick? How to calculator it ?

    asked by Vy on October 12, 2012
  4. physics

    A meter stick lies on the bottom of a 100 cm long tank with its zero mark against the left edge. You look into the tank at an angle of θ = 24°, with your line of sight just grazing the upper left edge of the tank, and h = 32 cm.

    asked by crystal on September 10, 2011
  1. Physics

    With the center of a meter stick place on a knife edge balance and a 2N weight hanging on its 100cm mark, where should a 5N weight be placed to keep the meter stick in static equilibrium.

    asked by Auguis, Jenesa on March 24, 2017
  2. Physics

    1. Does the center of gravity coincide with the fulcrum? Why? 2. why does a meter stick balance if the moments in one side equals the moment on the right side? 3. When do you solve for percent difference? Percent error?

    asked by help me please on April 6, 2016
  3. Science - Physics

    A meter stick is balanced at the 50-cm mark. You tie a 20-N weight at the 20-cm mark. At which mark should a 30-N weight be placed so that the meter stick will again be balanced?

    asked by Jen on July 6, 2010
  4. Physics

    A uniform meter stick balances on a fulcrum placed at the 40 cm mark when a weight W is placed at 30 cm mark. What is the weight of the meter stick? How to calculator it ?

    asked by Vy on October 12, 2012

You can view more similar questions or ask a new question.