What is the closest linear form for sequence given given a "small downward j"=-15 and a "small downward n"-8
To find the closest linear form for a given sequence, we need to determine the common difference between the terms.
In this case, a "small downward j" represents a decrease of 15, and a "small downward n" represents a decrease of 8. This suggests that the sequence is going in a downward direction.
Since the common difference is the same for both terms, we can conclude that the common difference of the sequence is -15.
To find the linear form of the sequence, we can use the formula for an arithmetic sequence:
\[An = A1 + (n-1)d\]
where An represents the nth term in the sequence, A1 is the first term, n is the position of the term in the sequence, and d is the common difference.
In this case, the first term (A1) is not given, so we cannot determine the exact linear form of the sequence without additional information.
However, if we assume A1 to be a constant value, we can write the linear form of the sequence as:
\[An = A1 + (n-1)(-15)\]
So, the closest linear form for the given sequence with a "small downward j" of -15 and a "small downward n" of -8 is:
\[An = A1 - 15n + 15\]
Please note that this is an approximation and assumes a constant value for A1. Additional information is necessary to determine the exact linear form of the sequence.