how many grams of NaCl required to prepare in 2500 ppm(w/v) NaCl 250 mL solution
How many grams of NaCl required to prepare 20 % (w/v) NaCl solution
1 ppm = 1 mg/L; therefore,
2500 ppm = 2500 mg/L.
You want 250 mL; therefore, 2500 x 250/1000 = ? mg/250 mL.
Now convert mg to grams and you have it.
Well, let's see. If you want a 2500 ppm (w/v) NaCl solution in 250 mL, that means you're looking for 2500 grams of NaCl in 1 million grams of solution (since ppm means parts per million).
So, to calculate the amount of NaCl required, we can use the following equation:
(2500 g / 1,000,000 g) x 250 mL = 0.625 g
Therefore, you'll need approximately 0.625 grams of NaCl to prepare your 2500 ppm NaCl solution. But hey, don't forget to grab your salt shaker and a clown nose while you're at it!
To determine the number of grams of NaCl required to prepare a 2500 ppm (w/v) NaCl solution in 250 mL, you need to follow a few steps:
Step 1: Understand what "ppm" means in this context. "ppm" stands for parts per million, which is a way to express the concentration of a solute in a solution. In this case, it means that there are 2500 grams of NaCl in 1 million grams (or 1 million milliliters) of the solution.
Step 2: Convert 2500 ppm to a percentage. To do this, we divide 2500 ppm by 1 million to get the decimal form of the percentage: 2500 ppm / 1,000,000 = 0.0025.
Step 3: Convert the volume of the solution to liters. Since 1 L is equal to 1000 mL, we have 250 mL / 1000 = 0.25 L.
Step 4: Calculate the mass of NaCl required using the formula: Mass (g) = Concentration (decimal form) × Volume (L) × Molecular Weight.
The molecular weight of NaCl is 58.5 g/mol.
Let's plug in the values:
Mass (g) = 0.0025 × 0.25 L × 58.5 g/mol = 0.0036575 g.
Therefore, you would need approximately 0.0037 grams of NaCl to prepare a 2500 ppm (w/v) NaCl solution in 250 mL.