# math

The position of a bucket falling down a well can be represented by the function h(t)=-16t^{2} where t is time in seconds and h(t) is measured in feet. Based on this function, what is the velocity of the bucket after it has fallen for 4 seconds?

1. dh/dt is the velocity (1st derivative)

v(t) = -32t

posted by Scott
2. So divide both sides by t and end up with v=-32? That doesn't seem right.

posted by Marissa
3. Never mind. I forgot about multiplying it by 4 because it's supposed to be the velocity for 4 seconds.

posted by Marissa
4. I am shocked to see your first try.

v(t) is a function.
it is v of t, not v times t!

posted by Steve

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