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How many grams of a solid mixture containing strontium chloride would one need to make 558 mL of a 0.100 M strontium chloride solution, if the solid mixture contains 58.6% strontium chloride by weight

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Anonymous

  1. How many mols do you need? That's M x L = mols. 0l00 x 0.558 L = ?
    Then grams = mols x molar mass = ?
    That's grams you need if the SrCl2 is 100%. It isn't so you need ?g from above/0.586 = ??

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    DrBob222

  2. 6.62 g

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    Masivuye

  4. 8.85 g

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    Masivuye

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