# Calculus

I need to find the exact solution to:
2sin2x = sqrt(x)on the interval (0,pi)

This is how I started it, but I don't think it's correct.

sin2x = sqrt(x)/2
2sinxcosx = sqrt(x)/2
sinxcosx = sqrt(x)/4

What do I need to do now?

need to find the exact solution to:
2sin2x = sqrt(x)on the interval (0,pi)
>>

I tried this before, and spend some time on it. I could not find an exact analytical solution, the best I could do was graph it. I tricd Taylor series, infinite series for sin x, nothing worked. I am certain whomever designed the question has something in mind, some trick, but I cant decipher it.

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