A Ball of Mass 0.5kg Moving At 10m/s Collide With Another Ball Of Equal mass At Rest.If The Two Balls Move Together After The Impact Calculate Their common Velocity

conserve momentum:

0.5*10 + 0.5*0 = (0.5+0.5)*v

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Mo men tum of two objects in before collision =momentum is of two object after collision,therefore 0.5 times 10-0.5 =0.5v +0.5v=v 5-0=v therefore, v=5ms-1

Thanks

0.5 (10) = (.5+.5) v V = 5m/s

To calculate the common velocity of the two balls after the impact, you can use the law of conservation of momentum. According to this principle, the total momentum before the collision should be equal to the total momentum after the collision.

The momentum (p) of an object is given by the product of its mass (m) and velocity (v), so p = m * v.

Let's denote the initial velocity of the first ball as v1i, the final velocity of the two balls as vf, and the mass of each ball as m.

Since the first ball is moving and the second ball is at rest, the momentum before the collision is:

p1i = m * v1i = 0.5 kg * 10 m/s = 5 kg·m/s

After the collision, the two balls will move together, so their final velocity will be the same. Thus, we have:

p1 + p2 = (m * vf) + (m * vf) = 2m * vf

The total momentum after the collision is equal to the momentum before the collision, so:

p1i = 2m * vf

Rearranging the equation, we find:

vf = p1i / (2m)
= 5 kg·m/s / (2 * 0.5 kg)
= 5 m/s

Therefore, the common velocity of the two balls after the impact is 5 m/s.

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