A line segment has one endpoint of A (2, -1) and a slope of 3/4. Find the coordinates of another possible endpoint B.

Too stupid to post

Idiot

To find the coordinates of the other endpoint, B, we need to use the point-slope form of a linear equation, which is:

y - y1 = m(x - x1)

where m is the slope and (x1, y1) is a point on the line.

Given that the slope is 3/4 and one endpoint is A (2, -1), we can substitute these values into the equation to find B.

Let's plug in the values:

y - (-1) = (3/4)(x - 2)

Simplifying further:

y + 1 = (3/4)(x - 2)

Now, we can rearrange the equation to solve for y:

y = (3/4)(x - 2) - 1

Next, we can choose any value for x and substitute it into the equation to find the corresponding y-coordinate of point B. Let's choose x = 0 for simplicity:

y = (3/4)(0 - 2) - 1
y = (3/4)(-2) - 1
y = -3/2 - 1
y = -3/2 - 2/2
y = -5/2

Therefore, the coordinates of the other possible endpoint, B, are (-2, -5/2).

we can find the equation of the line, you have the slope and a given point.

Once you have the equation, replace the x with anything you want, then find its matching y value