# physical science

How many minutes would be required for a 310.0 W immersion heater to heat 202.0 g of water from 22.0°C to 95.6°C?

1. Joules of energy required
... 202 * (95.6 - 22.0) * 4.18

divide by heater wattage
... 1 watt = 1 Joule per second

divide by 60 ... sec to min

posted by Scott

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