Ann and Tom want to establish a fund for their grandson's college education. What lump sum must they deposit at a 9.39% annual interest rate, compounded annually, in order to have $20,000 in the fund at the end of 10 years?
I cannot get the right answer.
so, why not show your work?
P(1+.0939)^10 = 20000
Now just solve for P.
Anna and Tom want to establish a fund for their grandson's college education.What lump sum must they deposit at an 8% annual interest rate, compounded monthly ,in order to have $60,000 in the fund at the end of 10 years.
To determine the lump sum that Ann and Tom must deposit, we can use the formula for compound interest:
FV = PV(1 + r/n)^(nt)
Where:
FV = Future Value
PV = Present Value (lump sum)
r = Annual interest rate (in decimal form)
n = Number of compounding periods per year
t = Number of years
In this case, the future value (FV) is $20,000, the annual interest rate (r) is 9.39%, compounded annually (n = 1), and the number of years (t) is 10.
Plugging in these values, we can solve for the present value (PV):
$20,000 = PV(1 + 0.0939/1)^(1*10)
Simplifying,
$20,000 = PV(1.0939)^10
Divide both sides of the equation by (1.0939)^10 to isolate PV:
PV = $20,000 / (1.0939)^10
Calculating this value, we find that the lump sum they must deposit is approximately $8,975.28.
To solve this problem, we can use the formula for compound interest:
A = P(1 + r/n)^(nt)
Where:
A = final amount
P = principal (initial deposit)
r = annual interest rate (as a decimal)
n = number of times interest is compounded per year
t = number of years
In this case, we want to find the lump sum deposit (P) that will result in a final amount (A) of $20,000 in 10 years.
Let's plug in the given values into the formula and solve for P:
A = $20,000
r = 9.39% = 0.0939 (as a decimal)
n = 1 (compounded annually)
t = 10 years
Now, the formula becomes:
$20,000 = P(1 + 0.0939/1)^(1*10)
Simplifying this equation:
$20,000 = P(1.0939)^10
Divide both sides of the equation by (1.0939)^10:
P = $20,000 / (1.0939)^10
Using a calculator to evaluate (1.0939)^10, we find:
P ≈ $9,312.24
Therefore, Ann and Tom would need to deposit approximately $9,312.24 as a lump sum in order to have $20,000 in the fund at the end of 10 years.