By letting x=5^y, show that the equation p5^y + 5^-y = 5 can also be written as px^2-5x+1 = 0

asked by Grace
  1. p5^y + 5^-y = 5
    p5^y + 1/5^y = 5
    now replace
    px + 1/x = 5
    times x
    px^2 + 1 = 5x
    px^2 - 5x + 1 = 0

    which is what we want

    posted by Reiny

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