# algebra

the sum of the digits of a three digit number is 20. the middle digit is equal to one fourth the sum of the other two. if the order of the digits be reversed the number increases the original by 198 find the original number

1. let the digit be abc

a+b+c=20

b=1/4(a+c)

100a+10b+c=100b+10c+b+198

now solve for abc and good luck

posted by collins
2. I coudnt solve.

posted by Rohan
3. I coudnt solve. Couldn't solve for abc

posted by Rohan

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