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Benzene (C6H6) has a normal freezing point of 5.50oC and a density of 0.88 g/mL. When 1.28 g of naphthalene (C10H8) is dissolved in 125 mL of benzene, the freezing point of the solution is 5.03oC. Determine the molal freezing point constant for this solvent.

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Sarah

  1. mass = density*volume
    mass benzene = 0.88 g/mL x 125 mL = ?

    delta T = Kf*m
    You know delta T.
    m = mols/kg solvent;
    mols naph = 1.28/molar mass naphthalene
    kg solvent = ? g benzene/1000
    Solve for Kf

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    DrBob222

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