Arrange the following in order of decreasing stability. A blank molecular orbital diagram (Part A 1 figure) has been provided to help you.
Rank the fluorine species from most to least stable. To rank items as equivalent, overlap them. F2, F2+, F2-

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  1. I have no idea what the diagram looks like. BUT wouldn't you expect the F2 atom to be MUCH more stable than either of the others. You will need the diagram to rank the other two. Fit the F^+2 and the F^-2 into the diagram.

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  2. The neutral species is not necessarily the most stable

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  3. Consider how bond order affects stability.

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  4. F^+2,F2,F2-

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  5. F2+, F2, F2- is the correct answer as stated by "..."

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  6. calculate bond order for each and compare using bond order=1/2(no of bonding electrons-no of antibonding electrons) but you must first draw the energy level diagrams

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