phy211

A car accelerates from rest at 2.0 m/s2 for 20 s. The speed then remains constant for 20 s, after which the car slows down with an acceleration of 3 m/s2 until the car stops. What is the total distance traveled?

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  1. first part
    final v = a t = 40 m/s
    average v = 20 m/s
    x = 0 + 20(20) = 400 m

    second part
    v = 40
    x = 400 + 40(20) = 1200 m

    third part
    Vi = 40
    average v = 20
    time = 40/3 = 13.3
    x = 1200+20(13.3) = 1466 m

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  2. 3066

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