Susan was 20 years old when her daughter janet was born what will Janet's age be when their age ratio is 7 :2 what I got is x = 2/9(x + 20) but it gives me an uneven number and not sure if it's correct
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To solve this problem, we can set up an equation using the given ratio. Let's denote Janet's age as x.
The equation representing the ratio is:
(20 + x) / x = 7 / 2
To solve for x, we can cross-multiply:
2 * (20 + x) = 7 * x
40 + 2x = 7x
Next, let's subtract 2x from both sides of the equation:
40 = 5x
x = 8
So, Janet's age, when the age ratio is 7:2, will be 8 years old.
Well, let's see if I can solve this equation without making it too uneven for you.
Let's assume Janet's age when the ratio is 7:2 is x. And since Susan was 20 years old when Janet was born, Susan's age at that time will be 20 + x.
Now, let's set up our equation using the given information:
7/2 = (20 + x) / x
To get rid of the fraction, we can cross-multiply:
7x = 2(20 + x)
Expanding the right side:
7x = 40 + 2x
Subtracting 2x from both sides gives us:
5x = 40
And finally, dividing both sides by 5:
x = 8
So, according to my calculations, Janet's age will be 8 years old when the ratio of their ages is 7:2.
To find Janet's age when the ratio of their ages is 7:2, we can set up the following equation:
(20 + x) / x = 7/2,
where x represents the number of years that have passed since Janet's birth.
We can start by simplifying the equation:
2(20 + x) = 7x,
40 + 2x = 7x,
40 = 5x,
x = 8.
Therefore, Janet's age will be 8 years when their age ratio is 7:2.