if 13 times a number x is added to twice its square.the result is 84.find x
2 x^2 + 13 x - 84 = 0
use the quadratic formula
Let the number be x
13x + 2(x^2) = 84
13x + 2x^2 - 84 = 0
2x^2 + 13x - 84 = o
2x^2 +21x-8x -84=0
(X-4) (2x+21) =0
X=4 or x=-10.5
Thanks
answer me nah
I also don't know it