the perimeter of a rectangle is 108 cm. if the length of the rectangle is 5 tikes the width what are the demensions of the rectangle

If the perimeter of a square is 108 centimeter what is the length of one side

Let's solve this step by step.

Step 1: Assign variables
Let's assume the width of the rectangle as "w" cm.
According to the problem, the length of the rectangle is 5 times the width, so the length will be "5w" cm.

Step 2: Calculate the perimeter
The perimeter of a rectangle is given by the formula:
Perimeter = 2 × (length + width)

So, the perimeter of this rectangle will be:
108 = 2 × (5w + w)

Step 3: Simplify and solve the equation
Let's simplify the equation:

108 = 2 × (6w)
108 = 12w
w = 108 / 12
w = 9

So, the width of the rectangle is 9 cm.

Step 4: Calculate the length
The length of the rectangle is 5 times the width, so:

Length = 5 × 9
Length = 45

So, the length of the rectangle is 45 cm.

Therefore, the dimensions of the rectangle are:
Width = 9 cm
Length = 45 cm

To find the dimensions of the rectangle, we'll start by setting up some equations based on the given information.

Let's assume the width of the rectangle is "x" cm.

We are told that the length of the rectangle is 5 times the width, so the length would be 5x cm.

The perimeter of a rectangle is calculated by adding up all the sides. In this case, the perimeter is given as 108 cm.

The formula for the perimeter of a rectangle is: P = 2(length + width)

Substituting the values, we have: 108 = 2(5x + x)

Simplifying the equation, we get: 108 = 2(6x)

Dividing both sides by 2, we have: 54 = 6x

Next, we'll solve for x by dividing both sides by 6: x = 9

Therefore, the width of the rectangle is 9 cm.

Since the length is 5 times the width, the length would be 5 * 9 = 45 cm.

So, the dimensions of the rectangle are: width = 9 cm and length = 45 cm.

P = 2L + 2W

108 = (2 * 5W) + 2W
108 = 12W
9 = W