A stone of mass 50g is accelerated from a catapult to a speed of 8.0 ms-1 from rest over a distance of 30 cm. What average force is applied by the rubber of the catapult ?

wrong the answer of the question is 5N

U= 0m/s

V= 8m/s
M= 50g =0.05kg
S=30cm =0.3m
t=?
F=?
S= (u+v/2) ×t
O.3= (0+8/2)t
0.3=4t
t= 0.3/4
t=0.075sec

Ft=M(V-U)
0.075F= 0.05×(8-0)
F=0.4/0.075
F= 5.33N

5N

Why did the stone go to the party? Because it was catapultivated!

But let's get serious for a second. To find the average force applied by the rubber of the catapult, we can use the kinematic equation:

v^2 = u^2 + 2as

where:
v = final velocity (8.0 m/s)
u = initial velocity (0 m/s, since it starts from rest)
a = acceleration
s = distance (0.30 m)

Rearranging the equation to solve for acceleration (a):

a = (v^2 - u^2) / (2s)

Substituting the given values:

a = (8.0^2 - 0^2) / (2 * 0.30)

Now we can solve for acceleration:

a = 106.6 m/s^2

To find the average force applied by the rubber of the catapult, we can use Newton's second law:

F = ma

Substituting the values:

F = (0.05 kg) * (106.6 m/s^2)

Calculating the average force:

F = 5.33 N

So, the average force applied by the rubber of the catapult is approximately 5.33 Newtons.

To find the average force applied by the rubber of the catapult, we can use Newton's second law of motion, which states that force (F) is equal to the mass (m) multiplied by the acceleration (a).

First, let's convert the mass of the stone from grams to kilograms.
Mass (m) = 50 g = 50/1000 kg = 0.05 kg

Next, we need to find the acceleration of the stone. We can use the kinematic equation:
v^2 = u^2 + 2as
where
v = final velocity = 8.0 m/s (given)
u = initial velocity = 0 m/s (since the stone is initially at rest)
a = acceleration
s = distance = 30 cm = 30/100 m = 0.3 m

Rearranging the equation, we get:
a = (v^2 - u^2) / (2s)
= (8.0^2 - 0^2) / (2 * 0.3)
= 64 / 0.6
= 106.67 m/s^2

Now we can calculate the average force using Newton's second law:
F = m * a
= 0.05 * 106.67
= 5.3335 N

Therefore, the average force applied by the rubber of the catapult is approximately 5.3335 Newtons.

average speed = (8+0)/2 = 4 m/s

so
t = .30 meters/4 meters/s =.3/4 s

Force * time = change of momentum
or impulse

F(.3/4) = .5 * 8

F = (5/3)(32) = 53.3 Newtons