I am confused need help
a computer store sold a total of 300 items last month. the store sold six times as many hard drives as they did CD-RoM drives, and half as many floppy drives as hard drives. Based on this information,, how many of each item were sold?
Let X = number of hd.
Y = number of cd
Z = number of fl/d.
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You know:
X + Y + Z = 300
The problem tells you that the store sold six times as many hard drives as cd Rom so you know 6Y = X.
The problem tells you that the store sold 1/2 as many floppy drives as hard drives; therefore, 1/2 X = Z
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Using X + Y + Z= 300, just substitute the value of Y in terms of X (from above which is Y= 1/6 X) and the value of Z in terms of X and solve for X.
I hope this helps. We shall be happy to check your work if you post it.
I really don't understand, i am new at this and have 4 anwser to it don't know which one because don't know how to get to the answer and they are:
1.30hd,90fl/d and 180 cd
2.40",20" and 240 "
3.180hd,90fl, and 30cd
4, 240hd, 20fl,and 40cd
My problem is how to get this anwser, could u explain to me how ge to the anwer of course knowing the anwer, i will understand.
If the store sold 1 cd / 6x as many hd = 6 / half as many floppy = 3 / 1 + 6 + 3 = 10.
They are sold in ratios of 10.
divide 10 into 300 etc etc dose this help.
mike
thanks i still don't get it but i am working on it. ok thanks again.
Obviously you have interpreted four different ways and three of those ways are not right. Do what I suggested and post your work so we can give you some guidance as to where you are going wrong. I have given you the three equations you need to solve the problem; the remainder is just arithmetic. I don't want to work the problem for you. I want you to understand how to do the problem.
Finding the area of a rectangle with 5 as one side and x+3 on the other.
Hey i said i love math no go screw a duck!
A computer store sold a total of 300 items last month. The store sold six times as many hard drives as they did CD-ROM drives, and half as many floppy drives as hard drives. Based on this information, how many of each items were sold?
I apologize if my previous response was not helpful. I understand that you are looking for an explanation of how to solve the problem.
To find the number of each item sold, we can set up a system of equations based on the given information:
Let X = number of hard drives
Y = number of CD-ROM drives
Z = number of floppy drives
From the problem statement, we know that the store sold six times as many hard drives as CD-ROM drives, and half as many floppy drives as hard drives. This can be written as:
X = 6Y (equation 1)
Z = 0.5X (equation 2)
We are also given that the store sold a total of 300 items, so:
X + Y + Z = 300 (equation 3)
Now we have a system of three equations with three variables. We can solve this system to find the values of X, Y, and Z.
One approach to solving this system is by substitution. We can substitute the expressions from equations 1 and 2 into equation 3:
6Y + Y + 0.5(6Y) = 300
Simplify the equation:
6Y + Y + 3Y = 300
10Y = 300
Y = 30
Now that we have the value of Y, we can substitute it back into equation 1 to find X:
X = 6Y = 6(30) = 180
Finally, we can substitute the values of X and Y into equation 2 to find Z:
Z = 0.5X = 0.5(180) = 90
Therefore, the number of each item sold is:
X = 180
Y = 30
Z = 90
So, the correct answer is option 3: 180 hard drives, 30 CD-ROM drives, and 90 floppy drives.
I hope this explanation helps you understand how to solve the problem. If you have any further questions, please feel free to ask.