Math(simple interest)

Mr.X invested a total of Rs.10,000 in three different accounts, the Accounts paid simple interest at an annual rate of 8%,9% and 7.5% respectively. Total interest earned for the year was Rs.845. The amount in the 9% account was twice the amount invested in the 7.5% account. How much did Mr.X invested in each account?

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  1. amount invested at 7.5% ---- x
    amount invested at 9% ----- 2x
    amount invested at 8% = 10000-2x-x = 10000 - 3x

    .08(10000-3x) + .09(2x) + .075x = 845
    times 1000
    80(10000-3x) + 90(2x) + 75x = 845000

    now it is easy, just solve for x, then back-substitute into my definitions

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