ChemistryStociometry

6.0g of cobolt (II) carbonate was added to 40cm3 of hydrochloric acid, concentration 2.0 mol/dm3. Calculate the maximum yield of cobalt (II) choloride-6-water and show that cobalt (II) carbonate was in excess.
CoCO3 +2HCl = CoCl2 +CO2 + H2O
CoCl2 + 6H2O = CoCl2.6H2O

what is the number of HCL moles used?

  1. 👍 0
  2. 👎 0
  3. 👁 341
asked by RM
  1. 1. Calculate moles of CoCO3
    =6.0/(58.933+12.0+3*16.0)
    =6.0/118.9
    =0.0504 mol

    2. Calculate moles of HCl
    =40/1000*2.0 mol
    =0.080

    Using stoiciometric ratios
    CoCO3 used = 0.08*1/2=0.04 mols
    => CoCO3 is in excess (<0.0504).

    The remaining answer can be obtained by finding the mass of 0.040 mol of CoCl2 and H2O respectively.
    [assuming choloride-6-water meant
    choloride-&-water]

    1. 👍 0
    2. 👎 0
    posted by MathMate

Respond to this Question

First Name

Your Response

Similar Questions

  1. Chemistry

    Can you check if this is correct please? a) How many moles of sodium hydroxide are there in 19.00 cm3 of 0.100 mol dm3? My answer: 0.0019 mol b) How many moles of hydrochloric acid are, there in 25.00 cm3 of the acid solution? My

    asked by Franky on October 16, 2011
  2. chemistry

    28cm3 of 0.2mol of sodium hydroxide was titrated against 25cm3 of hydrochloric acid using methyl orange as indicator, calculate the concentration in mol/dm3,calculate the concentration in g/dm3

    asked by rukayya on September 19, 2017
  3. chemistry

    5oocm3 of 1.0 mol dm3 of sodium hydroxide solution at room temperature was placed in a styrofoam cup and 25cm3 of 2.0 mol-dm3 of hydrochloric acid was added at the same temperature.The temperature rose by 15.2 degrees celsius.

    asked by marie haynes on March 8, 2015
  4. chemistry

    A is a solution of HCL containing 7.30g/dm3.B is a solution ofX2CO3 containing 10.6g/dm3.assume that average volume of acid is 2.81cm3 and the volume of base is 25.00cm3.from your result and information .calculate (I)concentration

    asked by john kelechi on May 26, 2014
  5. Chemistry

    “1.25 g of crushed limestone was added to 50.0 cm3 of 1.00 mol dm-3 hydrochloric acid (an excess). The mixture was left until all bubbling stopped and was then made up carefully to 250 cm3 with pure water. A 25.0 cm3 sample of

    asked by Sophia on November 10, 2010
  6. chem

    If 0.752 g of pure sodium carbonate was dissolved in water and the solution titrated with 25.90 mL of hydrochloric acid to a methyl orange end point, calculate the molarity of the hydrochloric acid solution. (Hint: This process

    asked by Beth on April 3, 2011
  7. Chemistry

    A is a solution of trioxonitrate (V) acid. HNO of unknown concentration B is standard solution of sodium hydroxide containing 4.00g per dm3 of solution 25cm3 portion solution B required an average of 24.00cm3 of solution A for

    asked by EMMANUEL on June 6, 2018
  8. CHEMISTRY

    A is a solution of trioxonitate acid of an unknown concentration, B is a standard solution of sodium hydroxide containing 4.00g per dm3 of solution 25cm3 portion of solution B require an average of 24cm3 of solution A for complete

    asked by Arowolo on July 11, 2018
  9. CHEMISTRY

    A is a solution of trioxonitate acid of an unknown concentration, B is a standard solution of sodium hydroxide containing 4.00g per dm3 of solution 25cm3 portion of solution B require an average of 24cm3 of solution A for complete

    asked by AROWOLO TEMITOPE on July 11, 2018
  10. Chemistry

    A is a solution of trioxonitrate (v)acid, HNO3 of unknown concentration.B is standard solution of sodium hydroxide containing 4.00g per dm3 of solution. 25 cm3 portion solution B required an average of 24.00cm3 of solution A for

    asked by Ogbaji on June 6, 2018

More Similar Questions