# calculus help

the bend moment M of a beam is given by dm/dx=-w(1-x) where w and l are constants.determine M in terms of x given that M=wl^2/2

plz show me working step

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1. dm/dx = -w(l-x)
dm = -w(l-x) dx
m = w(l-x)^2/2 + C

you cannot just say that M = wl^2/2

It has to be for some value of x. I presume you meant to say that

M(0) = wl^2/2

in which case C=0

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2. The bending moment M of the beam is given by dM/dx= -w(l-x) where w is a constant
Determine of M. Given M = ½ wt^2 when x=0

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