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evng .my teacher gave me this as a homework but i dnt undertand. 1.In a GP the 3rd term is equal to four times the first term and the sixth term is equal to three times the fourth term plus 32. Determine the sequence.
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The 3rd term of a geometric progression is nine times the first term.if the second term is onetwenty fourth the 5th term.find the 4th term. solution ar^2=9a r=sqr of 9 r=3.pls help me on how to get the first term(a)
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