# Math(A.P)

The fourth term of an A.P is equal to 3 times the first term and the seventh term exceeds twice the third term by 2. The first term and the common difference are:

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1. a+3d = 3a
a+6d = 2(a+2d)+2

now just crank it out.

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posted by Steve
2. The first term of ap exceed twice the second term by one . The 10th term exceed twice the fourth term by 3 find the first term

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