Algebra

1. Solve the equation below for x interms of a

4(ax+3)-3ax=25+3a

2. The formula for the sum of the degree measures of the interior angles of a polygon is S=180(n-2). Solve for n, the number of sides of the polygon, in terms of S.

IM STRUGGLING PLEASE HELP

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  1. these just use the normal sequences of operations...

    4(ax+3)-3ax=25+3a
    4ax+12-3ax = 25+3a
    ax+12 = 25+3a
    ax-3a = 25-12
    a(x-3) = 12
    a = 13/(x-3)

    S=180(n-2)
    S = 180n-360
    S+360 = 180n
    n = (S+360)/180 = S/180 + 2

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  2. 1.

    4 ( ax + 3 )-3 ax = 25 + 3a

    4 * ax + 4 * 3 - 3 ax = 25 + 3a

    4 ax + 12 - 3 ax = 25 + 3a

    4 ax - 3 ax + 12 = 25 + 3a

    ax + 12 = 25 + 3a Subtract 12 to both sides

    ax + 12 - 12 = 25 + 3a - 12

    ax = 25 - 12 + 3a

    ax = 13 + 3a Subtract 3a to both sides

    ax - 3a = 13 + 3a - 3a

    ax - 3a = 13

    a ( x - 3 ) = 13 Divide both sides by a

    x - 3 = 13 / a Add 3 to both sides

    x - 3 + 3 = 13 / a + 3

    x = 13 / a + 3 = 13 / a + 3a / a

    x = ( 13 + 3a ) / a

    2.

    S = 180 ( n - 2 ) Divide both sides by 180

    S / 180 = n - 2 Add 2 to both sides

    S / 180 + 2 = n - 2 + 2

    S / 180 + 2 = n

    n = S / 180 + 2

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  3. Where you got the s from ?

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  4. bosianian it said solve in terms of S

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  5. I solved it like:
    S=180(n-2) Distribute 180
    S=180n-360 Add 360
    S+360=180n Divide by 180
    S+2=n
    I’m confused as to what I am doing wrong.

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