A flat head drill bit is used to drill holes of small depth. The drill bit can drill holes with a diameter size of (40 ± 0.5)mm. The depth of the hole has an uncertainty of ±1mm.

If the total percentage uncertainty of the volume made by the hole is less than 10%, what is the minimum depth, in mm, which the drill bit can make?

My working:
V=π(r^2)d => d= 4V/(πD^2)
[V=Volume; r=radius; d=depth; D=Diameter]
△d/d = △v/v + 2(△D/D)
1/d = 10/100 + 2(0.5/40)
d=8

But the options given are 15, 14, 13 and 12. What am I doing wrong?

There's a small mistake in your calculation. Let me correct it for you.

The total percentage uncertainty formula for volume is given by:

ΔV/V = 2(ΔD/D) + Δd/d

Given that the total percentage uncertainty is less than 10%, we can rewrite this equation as:

2(ΔD/D) + Δd/d < 10/100

Substituting the values:

2(0.5/40) + Δd/(40 ± 0.5) < 0.1

0.025 + Δd/(40 ± 0.5) < 0.1

Now, to find the minimum depth, we would consider the worst case scenario, which is when the diameter is at its lowest value (40 - 0.5) and the depth is at its highest value (let's call it d_max).

0.025 + d_max/(40 - 0.5) < 0.1

0.025 + d_max/39.5 < 0.1

0.025*39.5 + d_max < 0.1*39.5

d_max < 0.1*39.5 - 0.025*39.5

d_max < 3.95 - 0.9875

d_max < 2.9625

Therefore, the minimum depth, rounded to the nearest whole number, is 2.

So, the correct answer is 2 mm. None of the options provided match this result. It seems like there may be an error either in the options or in the given information.

Your working is correct so far. You calculated the percentage uncertainty using the formula:

△d/d = △v/v + 2(△D/D)

Where △d is the uncertainty in the depth, △v is the uncertainty in the volume, and △D is the uncertainty in the diameter.

You correctly substituted the values into the formula:

1/d = 10/100 + 2(0.5/40)

Now, let's simplify the equation further:

1/d = 0.1 + 0.025

1/d = 0.125

To find d, we can take the reciprocal of both sides of the equation:

d = 1/0.125

d = 8

According to your calculations, the minimum depth should be 8 mm. However, the given options are different. This suggests that there might be an error in either the answer choices or the information provided.

I would recommend double-checking the given options or reviewing the problem statement to see if any information was missed or if there is a mistake in the options.