Algebra

Please help me with this Algebra problem:
The length of a rectangle is 91 less than six times the width of the rectangle. If the perimeter of the rectangle is 84 centimeters, what is the length of the rectangle? Write a system of equations for this situation and find its solution.

I have so far:

P = 2L + 2W
P = 2 (6x-91) + 2W
P = 12x -182 + 2W
2 (6x-91) =84
12x -182 =84
12x =266
Please help...I am confused...thank you

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asked by Leroy
  1. P = 2L + 2W
    84 = 2 (6W-91) + 2W
    84 = 14W - 182
    266 = 14W
    19 = Width

  2. Why do you have L's, W's and x's in your equation ?
    width ---- w
    length ---- l

    equation #1:
    2w + 2l = 84
    w+l = 42 **

    equation #2:
    "The length of a rectangle is 91 less than six times the width of the rectangle"
    ---> l = 6w - 91
    sub that back into **
    w + 6w-91 = 42
    7w = 133
    w = 133/7 = 19
    back in
    l = 6w-91
    = 6(19)-91 = 23

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    posted by Reiny

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