How long does a car with an acceleration of 2.0 m/s2 take to go from 10 m/s to 30 m/s
a. 3 m b. 6 m c. 18 m d. 36 m
v = Vi +a t
30 = 10 + 2 t
t = 10 seconds
but your answers are about distance
d = Vi t + (1/2) a t^2
d = 10(10) + 10^2 = 200 m
To find the time it takes for a car to go from an initial velocity of 10 m/s to a final velocity of 30 m/s with an acceleration of 2.0 m/s^2, you can use the following formula:
Final velocity (v) = Initial velocity (u) + (acceleration (a) * time (t))
In this case:
v = 30 m/s
u = 10 m/s
a = 2.0 m/s^2
Rearranging the formula to solve for time:
t = (v - u) / a
Substituting the given values:
t = (30 m/s - 10 m/s) / 2.0 m/s^2
t = 20 m/s / 2.0 m/s^2
t = 10 s
Therefore, it takes 10 seconds for the car to go from 10 m/s to 30 m/s with an acceleration of 2.0 m/s^2.
The correct answer choice is a. 10 seconds.
To answer this question, we can use the kinematic equation:
v = u + at
Where:
v = final velocity = 30 m/s
u = initial velocity = 10 m/s
a = acceleration = 2.0 m/s^2
t = time taken
Rearranging the equation:
t = (v - u) / a
Plugging in the values:
t = (30 - 10) / 2.0
t = 20 / 2.0
t = 10 seconds
So, the car takes 10 seconds to go from 10 m/s to 30 m/s.
Therefore, the correct answer is not provided in the options given.