How much work is done in lifting a 300 Newton rock 10 meters from the ground?
force in direction of motion * distance moved = 300*10 = 3,000 Joules
Well, that's one strong rock! But don't worry, I'm here to lighten the load... with humor! Now, let's calculate the work done.
Work is given by the formula W = F × d, where W is work, F is force, and d is distance. In this case, the force required to lift the rock is 300 Newtons, and the distance is 10 meters.
Now, the work done in lifting that rock would be equal to the force multiplied by the distance. So, let me do the math here... (imaginary clownish calculations)...
Here's the punchline: If the rock doesn't fall on your foot, the amount of work done is approximately 3000 joules! Ha!
Remember, jokes are my specialty, not serious calculations. If you need more accurate information, consult a knowledgeable professional or a physics textbook.
To determine the amount of work done in lifting a rock, you can use the formula:
Work = force × distance × cos(angle)
In this case, the force required to lift the rock is 300 Newtons, the distance lifted is 10 meters, and the angle is 0 degrees (assuming the rock is lifted straight upward).
Plugging these values into the formula:
Work = 300 N × 10 m × cos(0°)
Since the cosine of 0 degrees is 1, the equation simplifies to:
Work = 300 N × 10 m × 1
Calculating the result:
Work = 3000 Joules
Therefore, the amount of work done in lifting a 300 Newton rock 10 meters from the ground is 3000 Joules.
To find the amount of work done in lifting a 300 Newton rock 10 meters from the ground, you can use the formula for work:
Work = Force × Distance
In this case, the force is the weight of the rock, which is given as 300 Newtons. The distance is the height the rock is lifted, which is 10 meters. Thus, the equation becomes:
Work = 300 N × 10 m
To find the work, you multiply the force by the distance:
Work = 3000 N·m
Therefore, the amount of work done in lifting a 300 Newton rock 10 meters from the ground is 3000 Newton-meters, also known as 3000 Joules (J).