What is the ionic compound of SrMnO4
To determine the ionic compound of SrMnO4, we need to consider the charges of each individual ion.
First, let's look at the Sr ion. Sr belongs to Group 2 of the periodic table, so it has a +2 charge when it forms an ion. Therefore, the Sr ion is written as Sr2+.
Next, let's examine the MnO4 ion. Each oxygen atom in the MnO4 ion carries a charge of -2. Since there are four oxygen atoms in MnO4, the total charge from the oxygen atoms is -8.
To find the charge on the manganese (Mn) ion, we need to subtract the overall charge of the oxygen from the total charge of the MnO4 ion. The total charge of the MnO4 ion is 0 because it has no net charge. Therefore, the manganese ion must have a charge of +7 in order to balance the -8 charge from the oxygen atoms.
Now that we know the charges of each ion, we can write the chemical formula for the ionic compound. The compound of SrMnO4 consists of the Sr2+ ion and the MnO4- ion. Since the charges need to balance out, we need two Sr2+ ions for every one MnO4- ion. Thus, the ionic compound of SrMnO4 is Sr(MnO4)2.
Do you mean, What is the name?
Strontium permanganate