a body of massb20kg slides down a plane inclined at 30degree to the horizontal if a constant resting force of 40N act on the body it acceleration down the plane is what?
M*g = 20 * 9.8 = 196 N. = Wt. of body.
Fp = 196*sin30 = 98 N. = Force parallel to the incline.
Fp-40 = M*a.
98-40 = M*a, a = 58/M = 58/20 = 2.9 m/s^2.
To determine the acceleration of the body down the inclined plane, you can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.
In this case, the net force acting on the body is the component of the gravitational force parallel to the inclined plane, which can be calculated using the formula:
F = m * g * sinθ
Where:
F = net force
m = mass of the body (20kg in this case)
g = acceleration due to gravity (approximately 9.8 m/s^2)
θ = angle of inclination of the plane (30 degrees in this case)
Substituting the values into the equation:
F = 20kg * 9.8 m/s^2 * sin(30°)
F = 20kg * 9.8 m/s^2 * 0.5
F = 98 N * 0.5
F = 49 N
Now, we can determine the acceleration using Newton's second law:
F = m * a
Rearranging the equation:
a = F / m
a = 49 N / 20 kg
a = 2.45 m/s^2
Therefore, the acceleration of the body down the inclined plane is 2.45 m/s^2.