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solve: log8(w6)=2log8(w+15) note: the 8 is to be little at the bottom right corner of log
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How do I start to solve 2log8(x+1) = 8? I think 2log8(x+1) is log8^(x+1)to the 2nd but then what do I do because then I think I should do log8/log8 = x+1)^2 but that doesn't work at all Thank you for any help you can give
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Assume that x, y, and b are positive numbers. Use the properties of logarithms to write the expression logb ^8xy in terms of the logarithms of x and y. a. logb^8 + logb x + logb^y b. logb^8+logbx c. logb^8+logby d. logb^8 + log8 x
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Hi Reiny, I posted this problem earlier and you responded but I don't get the reasoning The problem was 2log8(x+1) = 8 you said multiply by 2 and then you put log8(x+1)=4(wasn't that dividing by 2) log8(x+1)^2 = 8 (how did
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Change the logarithmic equation to an equivalent equation involving an exponent. log8^64=2 **note that the 8 should be lower than the g** 8^(log64)=8^2 64=8^2 is this correct
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