In 1996,funding for a program increased by 0.21 billion dollars from the funding in 1995.In 1997,the increase was 1.05 billion dollars over the funding in 1996.For these years the funding was 10.23 billion dollars.How much was funded in each of these three years?
To find out the funding for each of the three years, we can use a systematic approach:
Let's assume the funding for the program in 1995 was "x" billion dollars.
In 1996, the funding increased by 0.21 billion dollars from the previous year. Therefore, the funding in 1996 would be: x + 0.21.
In 1997, the funding increased by 1.05 billion dollars from the previous year (1996). So, the funding in 1997 would be: (x + 0.21) + 1.05.
The total funding for all three years is given as 10.23 billion dollars. Therefore, we can set up the equation:
x + (x + 0.21) + 1.05 = 10.23.
Now, let's solve the equation to find the value of x:
2x + 1.26 = 10.23.
Subtracting 1.26 from both sides, we get:
2x = 10.23 - 1.26,
2x = 8.97.
Dividing both sides by 2, we find:
x = 4.485.
So, the funding in 1995 was approximately 4.485 billion dollars.
Now, we can calculate the funding for each of the three years:
1995: 4.485 billion dollars.
1996: 4.485 + 0.21 = 4.695 billion dollars.
1997: 4.695 + 1.05 = 5.745 billion dollars.
Therefore, the funding for each of the three years is as follows:
1995: 4.485 billion dollars.
1996: 4.695 billion dollars.
1997: 5.745 billion dollars.