Julie went to the post office and bought both $0.49 stamps and $0.34 postcards for her office's bills. She spent $62.60. The number of stamps was 20 more than twice the number of postcards. How many of each did she buy?
follow the same method and steps I just showed you in your other posts.
The two questions are of the same structure.
wheres the previous post at? Maybe it will help with my original question as it is almost identical to this problem
To solve this problem, we need to set up a system of equations based on the given information. Let's say Julie bought x number of postcards and y number of stamps.
According to the problem, the cost of each postcard is $0.34. So the total cost of postcards can be calculated as 0.34x.
Similarly, the cost of each stamp is $0.49. So the total cost of stamps can be calculated as 0.49y.
The total amount Julie spent is given as $62.60. Therefore, we can set up the equation: 0.34x + 0.49y = 62.60 ....(Equation 1)
It is also mentioned that the number of stamps was 20 more than twice the number of postcards. Mathematically, this can be written as: y = 2x + 20 ....(Equation 2)
Now, we have a system of two equations with two variables. We can solve this system to find the values of x and y.
One way to solve this system of equations is by substitution. Let's solve it step by step:
Step 1: Substitute Equation 2 into Equation 1.
0.34x + 0.49(2x + 20) = 62.60
Step 2: Simplify the equation.
0.34x + 0.98x + 9.8 = 62.60
Step 3: Combine like terms.
1.32x + 9.8 = 62.60
Step 4: Move the constant term to the other side.
1.32x = 62.60 - 9.8
1.32x = 52.80
Step 5: Divide both sides of the equation by 1.32 to solve for x.
x = 52.80 / 1.32
x = 40
So, Julie bought 40 postcards.
Step 6: Substitute the value of x into Equation 2 to find y.
y = 2(40) + 20
y = 80 + 20
y = 100
Therefore, Julie bought 40 postcards and 100 stamps.