suppose 45 students in an organization are male and 55 are female. Ten females and 15 males in the organization are graduating students. What is the probability that a:
a.) student chosen at random is male or a graduating student?
b.) students chosen at random is female graduating student?
To solve these probability questions, we first need to determine the total number of students in the organization. In this case, we know that there are 45 male students and 55 female students, which gives us a total of 45 + 55 = 100 students.
a.) To find the probability that a student chosen at random is male or a graduating student, we need to find the number of students who are either male or a graduating student, and divide it by the total number of students in the organization.
First, let's find the number of graduating students. We know that there are 10 female graduating students and 15 male graduating students, which gives us a total of 10 + 15 = 25 graduating students.
Next, let's find the number of male students who are not graduating. We subtract the number of male graduating students from the total number of male students: 45 - 15 = 30 male students who are not graduating.
To find the probability, we add the number of male graduating students and male students who are not graduating: 15 + 30 = 45 male students who are either male or graduating.
Finally, we divide the number of male students who are either male or graduating by the total number of students: 45/100 = 0.45. Therefore, the probability that a student chosen at random is male or a graduating student is 0.45, or 45%.
b.) To find the probability that a student chosen at random is a female graduating student, we need to find the number of female students who are graduating and divide it by the total number of students in the organization.
We know that there are 10 female graduating students, so we simply divide this number by the total number of students: 10/100 = 0.1. Therefore, the probability that a student chosen at random is a female graduating student is 0.1, or 10%.