physics

A uniform ladder of length 20.0m and weight 750 N is propped up against a smooth vertical wall with its lower end on a rough horizontal surface. The coefficient of friction between the ladder and this horizontal surface is 0.40.

(b) Work out and add the numerical values of each force clearly showing your justification in each case.

(c) Hence, calculate a value for the angle between the ladder and the wall if the ladder just remains in stable equilibrium

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  1. at top
    force to left from wall = Fxt
    vertical force from wall = 0
    at bottom
    Force up from floor = Fzb
    max force to right from floor =Fxb
    = .4 Fzb
    Gravity force down at 10 meters from base = 750 N

    not accelerating so
    Fzb = 750
    Fxb = .4(750)
    so
    Fxt also = .4(750) but to left

    angle to floor = T
    take moments about center of ladder
    Fzb (10 cos T) = Fxb (10 sin t) + Fxt(10 sin T)

    750 cos T = 2 (.4*750) sin T

    tan T = 1/.8

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    posted by Damon

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