The block of mass 2.13615 kg has an acceler- ation of 3.7 m/s2 as shown.
What is the magnitude of F? Assume the acceleration due to gravity is 9.8 m/s2 and the surface is frictionless.
Answer in units of N.
To find the magnitude of the force (F), we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
So, we have:
Mass of the block (m) = 2.13615 kg
Acceleration (a) = 3.7 m/s^2
Using Newton's second law of motion:
F = m * a
Substituting the given values:
F = 2.13615 kg * 3.7 m/s^2
Now, let's calculate the force:
F = 7.898105 N
Therefore, the magnitude of the force (F) is approximately 7.898105 N.
To find the magnitude of force (F), we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
Given:
Mass (m) = 2.13615 kg
Acceleration (a) = 3.7 m/s^2
Applying Newton's second law:
F = m * a
Substituting the given values:
F = 2.13615 kg * 3.7 m/s^2
Calculating the product:
F = 7.8989555 kg⋅m/s^2
Since the unit of force is Newton (N), we convert the answer to Newtons:
1 N = 1 kg⋅m/s^2
Therefore, the magnitude of force (F) is approximately 7.8989555 N.