Chemistry

How much sulphuric acid containing 90% H2SO4 by wt. is needed for the production of 1000 kg of HCl containing 42% HCl by weight in this reaction.

2NaCl + H2SO4 -----> Na2SO4 + 2HCl

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  1. mass HCl needed is 1000 kg x 0.42 = 420 kg or 420,000 g HCl, then mols HCl = 420,000/molar mass HCl = ?

    Using the coefficients in the balanced equation, convert mols HCl to mols H2SO4.
    Then grams H2SO4 (at 100%) = mols H2SO4 x molar mass H2SO4 = ?
    Since it is only 90% pure, you will need ?g H2SO4/0.90 = ?

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  2. 626.484kg

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  3. How did you got the answer show full steps!!

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  4. No proper answer. Actual answer is 628kg

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