algebra

Find the perimeter of the triangle whose vertices are the following specified points in the plane? (0,-3), (-2,1) and (-4,6)

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  1. To find the distance between two points (x1, y1) and (x2, y2), all that you need to do is use the coordinates of these ordered pairs and apply the formula:

    Distance = √((x2 − x1)^2 + (y2 − y1)^2)

    So, in using this formula, we find that:

    1. The distance between (0, -3) & (-2, 1) is √(20)

    2. The distance between (-2, 1) & (-4, 6) is √(29)

    3. The distance between (0, -3) & (-4, 6) is √(97)

    Thus, the perimeter is the sum of these three distances.

    √(20) + √(29) + √(97) = roughly 19.706

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