# algbebra

The fifth term of an A.p. Exceeds the second term by 1.The tenth term exceeds twice the fourth term by 3
* find first term and common difference
* sum of first twenty-five terms.

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1. cd = 1 / (5 - 2) = 1/3

t = f + 6 cd

t = 2f + 3 = f + 2
... 4th = -1
... 1st = -1 - (3 * 1/3) = -2
... 25th = -2 + (24 / 3) = 6

s = (-2 + 6) * (25/2)

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posted by Scott

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