The first ionization energy of Boron is 799, give an equation illustrating first ionization with Boron
To illustrate the equation for the first ionization of boron, we can represent it as:
Boron (B) + Energy → Boron ion (B+) + Electron (e-)
This equation represents the process in which a boron atom loses one electron to form a positively charged boron ion. The first ionization energy (799 kJ/mol) is the amount of energy required to remove one electron from a mole of gaseous boron atoms in their ground state.