Chemistry

The specific heat of a metal was found to be 0.38 J/g*°C. When 0.5007 g of this metal was heated in a stream of chlorine gas, it produced 1.0586 g of a metal chloride, MClx.

a. Determine the formula of the metal chloride and the accurate atomic weight of the metal.
b. What is the color of the chloride?

  1. 0
  2. 0
  3. 30
asked by Anonymous
  1. I don't believe this problem can be solved without using the 0.38 J/g*C as a starting point. I looked that up in a table and found the two closest elements were Zn and Cu. Basically, then, we decide which is the right one.
    ........M + Cl2 ==> MCl2
    ....0.5007 + x .....1.0586
    so g Cl2 must be 1.0586-0.5007 = 0.5579 g

    mols unknown = 0.5007/atomic mass Zn
    mols Cl = 0.5579/35.45 = ?
    Find the ratio; it is about 1 to 1.84 which isn't quite 1 to 2. Try Cu the same way and you get mols Cu 1 to mols Cl 1.99 so I would choose Cu as the unknown metal and the formula of MClx as CuCl2. That color is green

    Now for the more exact atomic mass of Cu.
    In the formula 1 mol M forms 1 mol MCl2.
    mols CuCl2 = grams CuCl2/molar mass CuCl2.
    mols Cl2 used = 0.5579/2*35.45 (but you need to look up atomic mass Cl and do this more accurately). Finally, mols CuCl2 = g CuCl2/molar mass CuCl2. You know mols and g, solve for molar mass CuCl2. That's approx 134. Then subtract 2*atomic mass Cl to find accurate atomic mass Cu.

    Repost at the top of the page if you have questions since this has slipped to page 3 or 4 on this forum.

    1. 0
    2. 0
    posted by DrBob222

Respond to this Question

First Name

Your Response

Similar Questions

  1. Chemistry

    55 kJ of heat are added to 200 kg of a metal at 28.00◦C and the temperature rises to 29.18◦C. What was the metal? 1. tungsten (specific heat = 0.134 J/g · ◦ C) 2. copper (specific heat = 0.385 J/g · ◦ C) 3. silver
  2. ocean county college

    A 150 g sample of metal at 55.0 C raises the temperature of 150 g of water from 23.0 C to 35.0 C. Determine the specific heat of the metal in J/g C. Hint: #1 First find heat absorbed by water using formula q = mass x specific heat
  3. chemistry

    3. Based on your answer in question 2, determine the percent error of your calculated specific heat capacity value of your unknown metal using the specific heat capacities of known metals below. Metal Specific Heat Capacity Nickel
  4. Chemistry

    Can someone please help me with the following? How do I find the specific heat of a metal when the only information I have is a temperature change ( of -73 degrees C) and a mass (of 22.53 grams)? And what is the forumla for
  5. Chemistry

    Use the calculation of specific heat for your metal as an example and determine the effect on specific heat if the sample temperature is changed. Does this small loss in heat significantly (>5%) affect your value for the specific
  6. Chemistry

    The specific heat of copper metal was determined by putting a piece of the metal weighing 33.6 g in hot water. The quantity of heat absorbed by the metal was calculated to be 47 J from the temperature drop of the water. What was
  7. Chemistry

    The specific heat of copper metal was determined by putting a piece of the metal weighing 39.4 g in hot water. The quantity of heat absorbed by the metal was calculated to be 47 J from the temperature drop of the water. What was
  8. Science

    The specific heat of copper metal was determined by putting a piece of the metal weighing 33.6 g in hot water. The quantity of heat absorbed by the metal was calculated to be 47 J from the temperature drop of the water. What was
  9. Chemistry

    The specific heat of copper metal was determined by putting a piece of the metal weighing 33.6 g in hot water. The quantity of heat absorbed by the metal was calculated to be 47 J from the temperature drop of the water. What was
  10. chemistry

    A sample of unknown metal has a mass of 36.7 g. This metal was placed in boiling water at 96.0oC until the metal had reached the temperature of the water. The metal was then placed in a foam cup with 50.0 g of water in it at

More Similar Questions