The compound copper(II) nitrate is a strong electrolyte. Write the reaction when solid copper(II) nitrate is put into water:

The compound copper(II) nitrate, Cu(NO3)2, dissociates completely in water to form copper(II) ions, Cu2+, and nitrate ions, NO3-. The chemical equation for the reaction is:

Cu(NO3)2(s) + H2O(l) → Cu2+(aq) + 2NO3-(aq)

In this equation, (s) indicates a solid state, (l) indicates a liquid state, and (aq) indicates an aqueous (dissolved) state.

To determine the reaction when solid copper(II) nitrate (Cu(NO3)2) is put into water, we need to remember that it is a strong electrolyte. This means it will dissociate completely into its constituent ions when it comes into contact with water.

The chemical equation for the reaction can be written as:
Cu(NO3)2 (s) + H2O (l) → Cu2+ (aq) + 2NO3- (aq)

In this equation, the solid copper(II) nitrate dissociates in water to form copper ions, Cu2+, and nitrate ions, NO3-. The reaction is represented with the state symbols "(s)" indicating the solid reactant and "(aq)" indicating aqueous solution in which ions are present.

It is worth noting that the water molecule (H2O) remains intact in this reaction and is not chemically altered.

Remember, the understanding of strong electrolytes allows us to predict the dissociation of compounds in water. In this case, copper(II) nitrate is a strong electrolyte, and hence it fully dissociates.

Cu(NO3)2(s) + H2O(l) ==> Cu^2+(aq) + 2NO3^-(aq)