What is the frequency and wave number associated with light of wavelength equal to 6000 angstrum
Velocity of light (c) = 3*10^8 m/s
You should know velocity = wavelength * frequency
Convert the wavelength into meters and solve put it in the above equation. You should get the answer.
And yeah, I ain't no engineer.
Note that you will need to change A to meters; also, wave number = 1/wavelength
To find the frequency and wave number associated with light of a given wavelength, we can use the following equations:
1. Frequency (ν) = speed of light (c) / wavelength (λ)
2. Wave Number (k) = 2π / wavelength (λ)
Given that the wavelength (λ) is equal to 6000 angstroms, we can substitute this value into the equations to find the frequency and wave number.
1. Frequency (ν) = speed of light (c) / wavelength (λ)
Speed of light (c) has a constant value of approximately 3 x 10^8 meters per second.
Convert 6000 angstroms to meters: 6000 angstroms * 10^(-10) meters/angstrom = 6 x 10^(-7) meters.
Substituting the values: Frequency (ν) = (3 x 10^8 m/s) / (6 x 10^(-7) m)
Simplifying: Frequency (ν) ≈ 5 x 10^14 Hz
Therefore, the frequency associated with light of wavelength 6000 angstroms is approximately 5 x 10^14 Hz.
2. Wave Number (k) = 2π / wavelength (λ)
Substituting the values: Wave Number (k) = 2π / (6 x 10^(-7) m)
Simplifying: Wave Number (k) ≈ 10^7 m^(-1)
Therefore, the wave number associated with light of wavelength 6000 angstroms is approximately 10^7 m^(-1).