# physics

a particle is projected horizontally at 15m/s from a height of 20m calculate the horizontal distance covered by the particle just before hitting the ground (g=10m/s*2)

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1. 20 = (1/2)10 t^2
solve for t = 2 seconds

d = 15 t =15*2 = 30 m

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2. 30m

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3. An object is projected with a velocity of 100m/s from the ground level at an angle tera to the vertical.if the total time of flight of the projectiles is 10s,calculate teta

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